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oct

def oct(value: Scalar, /, *, prefix: StaticString = "0o") -> String

Returns the octal string representation of an integer.

The string is prefixed with "0o" by default. Negative values start with a minus sign, like -0o173.

For example:

print(oct(64))  # 0o100
print(oct(-123))  # -0o173
print(oct(64, prefix=""))  # 100

Args:

value (Scalar): The integer value to format.
prefix (StaticString): The prefix prepended to the digits (defaults to "0o").

Returns:

String: A string containing the octal representation of the value.

def oct[T: Intable, //](value: T, /, *, prefix: StaticString = "0o") -> String

Returns the octal string representation of a value.

The value is converted to Int and formatted in base 8, prefixed with "0o" by default.

Parameters:

T (Intable): The type of the value. Must conform to Intable.

Args:

value (T): The value to format.
prefix (StaticString): The prefix prepended to the digits (defaults to "0o").

Returns:

String: A string containing the octal representation of the value.

def oct(value: Scalar[DType.bool], /, *, prefix: StaticString = "0o") -> String

Returns the octal string representation of a bool value.

The bool is formatted as an integer, so the result is 0o0 or 0o1 with the default prefix.

Args:

value (Scalar[DType.bool]): The bool value to format.
prefix (StaticString): The prefix prepended to the digits (defaults to "0o").

Returns:

String: A string containing the octal representation of the bool.